If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2-11=5x+13
We move all terms to the left:
x^2-11-(5x+13)=0
We get rid of parentheses
x^2-5x-13-11=0
We add all the numbers together, and all the variables
x^2-5x-24=0
a = 1; b = -5; c = -24;
Δ = b2-4ac
Δ = -52-4·1·(-24)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-11}{2*1}=\frac{-6}{2} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+11}{2*1}=\frac{16}{2} =8 $
| 2b+10=13 | | -17x-8+×=24 | | 6+2r=18 | | (90-1x)-1x=18 | | 14/38=x/28 | | F(x)=-2/3x+1 | | 0=-4(-4d-5) | | 8x+4(4x-3)=5 | | 4x+5/2=x/4+6 | | 0=(-5f+8)*4 | | 0=(5f+8)*4 | | 5+0.50x=25 | | 5+0.50x=39 | | 5.24x7.1=37.204 | | 3x-2x+27=8x-8 | | 2x+4-2=4 | | ?x?=-4/5 | | 2x-(7x-4)=29 | | -3=-x/5 | | 144-x=99 | | 2y=6+(14+y) | | -126=-3(7-5m) | | 3(1-+p)=-5(p+1 | | -7+7x=-126 | | 9^(x+3)=9^(3x-17) | | 5=-5p-10 | | 9+5x=x-23 | | (10x+5)=(6x-1)=180 | | 4m+5=-5 | | 4(x+32)+4(x+32)=16 | | -4x-2(2x+10)=109 | | 2⋅(x−7)=−20 |